Monday, February 7, 2011

Grade 8 Science February 8, 2011

Fantastic Fluids is our unit of study:

Here is the question; Water has a density of 1.0 g/mL... gold has a density of 19.32 g/cm^3. What volume would a 4.6g chunk of gold need to occupy to float?

See you soon!

4 comments:

  1. by my calculations....
    :)
    V = M/D

    4.6g / 19.32 g/cm^3
    =0.02380952 cm^3
    rounded 0.024 cm^3

    The 4.6g chunk of gold would need a volume of 0.024 cm^3 to float.... I hope!

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  3. Your idea was a good one, (I think you added an order of magnitude...one too many decimal moves) but you are making the assumption that the bar of Gold still has a density of 19.32... while this is true for most situations, you don't want it to be!

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  4. by my RE-calculations...(:

    you would need a volume of 1.1 to float the gold chunk but that still make no sense i am submitting it any ways! :)

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